X^2+3y+90=180

Solution for X^2+3y+90=180 equation:

X^2+3X+90=180

We move all terms to the left:

X^2+3X+90-(180)=0

We add all the numbers together, and all the variables

X^2+3X-90=0

a = 1; b = 3; c = -90;
Δ = b2-4ac
Δ = 32-4·1·(-90)
Δ = 369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{369}=\sqrt{9*41}=\sqrt{9}*\sqrt{41}=3\sqrt{41}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3\sqrt{41}}{2*1}=\frac{-3-3\sqrt{41}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3\sqrt{41}}{2*1}=\frac{-3+3\sqrt{41}}{2}
$